How do you calculate serial dilutions? + Example - Socratic
2014年6月18日 · You multiply the original concentration by the dilution factors for each dilution. A serial dilution is any dilution in which the concentration decreases by the same factor in each …
How do you calculate dilution factor? + Example - Socratic
2014年3月22日 · EXAMPLE 2: How would you make 500 mL of a 1:250 dilution? Solution: "DF" = V_f/V_i V_i = V_f/("DF") ="500 mL"/250 = "2.00 mL" Pipet 2.00 mL of your stock solution into a …
What weight of potassium permanganate is required to produce …
2017年12月11日 · "2 g" The idea here is that you need to start from the diluted solution and work your way back to the original solution. So, you know that a solution's mass by volume percent …
Dilution Calculations - Chemistry - Socratic
After performing a dilution calculation, you determine you need 25.0 milliliters of an aqueous stock solution to make 100.0 milliliters of a new solution. How would this be prepared? A #295*mL# …
What is the weight per volume method to calculate concentration?
2015年1月1日 · A weight/volume percent concentration ("w/v%") is defined as mass of solute divided by volume of solution and multiplied by 100%. The mathematical expression for a …
How do you solve #10^ (4x -1) = 1000# and find any ... - Socratic
2018年5月5日 · The only solution is x=1. Rewrite 1000 as 10^3: 10^(4x-1)=1000 10^(4x-1)=10^3 Now, since the bases are the same, the exponents must be equal to each other: …
Find the solution to the system of equations Log (2000xy ... - Socratic
2018年6月27日 · Eliminate variables one by one, then substitute back. We obtain two solution sets for (x,y,z): (1,5,1) and (100,20,100).
How do you write log_10 (1/1000)=-3 in exponential form? - Socratic
2017年1月21日 · log_ba=m rArr b^m=a :. log_10 (1/1000)=-3 rArr 10^-3=1/1000.
What’s 8 over 1000 as a percentage? - Socratic
2018年4月3日 · 8/1000=0.8% A percentage is something out of a hundred. In this case, we can get the denominator to be 100 if we divide both the numerator and denominator by 10: …
How do you solve #(1/1000)^(-1/3)#? - Socratic
2018年3月30日 · 10 (1/1000)^-(1/3) =1/1000^-(1/3) =1000^(1/3) =root(3) 1000 =10. What are commonly used math terms that translates to addition, subtraction, multiplication, and division?